|
|
Reason #4 why the Wizard likes Bodog:
One-stop shopping
Bodog offers the triple crown of gambling: casino, poker, and sports. Many other casinos have tacked on poker as an afterthought, and many poker rooms have tacked on a casino as an afterthought, and the lack of attention shows, sometimes painfully. And very few of these sites let you make sports wagers. But Bodog doesn't just offer all three, they do each one well, and everything's integrated. It's easy to play all three off one deposit, off just one account. Another nice thing about Bodog is that you don't need a separate account to play casino games with fake money. In fact you do not even need an account for that at all, you can just click over there and play. Finally, Bodog usernames are only six or seven characters long making them possible to remember. By contrast some competitors' usernames are extremely long and cumbersome. (Visit Bodog) One click and you're in:
No popups, no download, no registration, no B.S., just the game. See important note about Bodog payouts & deposits. |
|
|
|
|
|||||
|
|||||
|
Home • What's New • Advice & Strategy • Ask the Wizard • Gambling online • Play for Fun |
|||||
Why are the odds of a hard four different from the odds of a hard six? Isn't there just one way out of thirty-six possible combinations to hit doubles (double 1,2,3...)? – James from Santa Cruz
Yes, the probability of each double is 1/36. However, you have to compare that to the probability of rolling a losing combination. For a hard four, there are 8 losing rolls (two each of 1-6, 2-5, 3-4, and 1-3), so the probability of winning is 1/9. For a hard six, there are ten losing rolls (two each of 1-6, 2-5, 3-4, 1-5 and 2-4), so the probability of winning is 1/11. The hard six pays more because the probability of winning is less. November 4, 2007
I rolled four hard 4's without rolling a 7 or an easy 4. Any idea what the odds on doing that is? Can it be calculated? The probability of winning the hard 4 bet is 1/9. So the probability of winning four times in a row is (1/9)4 = 1 in 6561. Aug. 25, 2003 On average, after establishing a point in craps how often will the player make the point? Given that a point was made 5/12 of the time it will be a 6 or 8, 4/12 a 5 or 9, and 3/12 a 4 or 10. The probability of making a 6 or 8 is 5/11, a 5 or 9 is 4/10, and a 4 or 10 is 3/9. So the probability of making a point, given that a point was established is, (5/12)*(5/11)+(4/12)*(4/10)+(3/12)*(3/9) = 40.61%. June 27, 2003 Based on approximately 150 rolls per hour in dice, how many decisions with regard to the point will be made. I was told by someone that there is a decision every 3.6 rolls. Is this correct? - Jeff from Las Vegas, US The following are the possible outcomes of the pass/come bet and their associated probabilities: First let me say I think your web site is absolutely
outstanding. Thanks. I watched a new craps game being played
at Grand Casino, Biloxi, MS. called "Four The Money". To win
the shooter must throw the dice 4 times without a 7 coming
up. What are the odds of throwing the dice: You're welcome, thanks for the kind words. The probability of throwing the dice n times without a 7, and then throwing a 7, is (5/6)n*(1/6). The probability of throwing n non-sevens, without specifying the next throw would be (5/6)n. So the probability of throwing the dice at least four times without a seven would be (5/6)4=625/1296=0.4823. Mar. 6, 2002 On average, during the course of 100 points being established in craps: (1) How many of those would be 4/10, 5/9 or 6/8, (2) During the 100 how many times would each pass (4/10, 5/9, 6/8) vs. a 7 being rolled. - Jon Moriarty from Danville, New Hampshire 25 would be on 4 and 10, 33.33 on 5 and 9, and 41.67 on 6 and 8. (2) Out of 100 points established a win on 4 or 10 would occur 8.33 times, on 5 or 9 would occur 13.33 times, and 6 or 8 would occur 22.73 times. Jan. 14, 2001 Do you have any idea what the "record" is for the most sevens thrown with a pair of fair dice in craps is? I had someone tell me it was 84, but the odds against that many sevens in a row being thrown is so long I'm skeptical. It seems it's more possible that 84 consecutive passes have come out, but even that's a million to one shot (figuratively--literally, it's much worse). I tried to look on the Web but have no idea where I would find something like that. ñ Mike Manuel from ? All I know is that a downtown Las Vegas casino, I think the Californian, boasts of being the home of the longest single shooter in craps history. I think his roll lasted about three hours. How many times he rolled I do not know. The probability of rolling 84 sevens in a row is 1 in 50,021,738,714,629,100,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000 (rounded). The probability of winning 84 pass line bets in a row is 1 in 534,241,247,406,472,000,000,000,000(rounded). I doubt that either has ever happened. Dec. 31, 2000 How often can you roll a pair of dice 28 times without getting a 7? How do you figure this? Congratulation on your site, it's great. - Arturo Gomez from Mexico City, Mexico Thanks for the compliment. I take it you mean what is the probability of rolling a pair of dice 28 times without getting a 7. The probability of not rolling a 7 on any one roll is 5/6. The probability of not rolling a 7 in 28 rolls is (5/6)28 = 0.006066, or about 1 in 165. Oct. 5, 2000 Q: What are the odds (and frequency) in 100,000 rolls of the dice (craps/dont pass line) of losing a DP bet 2x's.3x's 4x's 5x's 6x's 7x's 8x's or 9x's in a row. - Derick from Minneapolis, USA A: My craps appendix shows how to work out the odds for any one bet. There you will see the probability of losing the don't pass bet is 2928/5940. The probability of losing n bets in a row is (2928/5940)n. The frequency in 100,000 of losing n is a row is 100,000 * (2928/5940)n, assuming that each roll is the beginning of a new sequence. In other words counting overlapping DP streaks. Note that this also counts ties as breaking a series. Aug. 20, 2000 Q: What is the average number of rolls (throws?) till a shooter "sevens out"? I know that a 7 will appear every 6 rolls, but with come-out 7-11s and craps, plus the possibility of shooters making multiple points, I think the average number of rolls may be higher than expected. Is there any mathematical reference material on this? - Grshooter from Kansas City, Missouri
See important note about Bodog payouts & deposits. ©1998-2008 Wizard Of Odds Consulting, Inc. All rights reserved. Privacy/Terms Contact Advertise About Us Links
The Wizard's other sites:
Wizard of Macau,
Sweat the Money,
Math Problems
The Wizard's recommends: Casino Meister, Online Casino City, Online Poker Room Reviews, (See more of the Wiz's picks) | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
Ask the Wizard: